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What does this calculator estimate?
Replace $80,000 of income for 10 years, clear $300,000 of debt, fund $100,000 of college, and subtract $50,000 of assets: a $1,150,000 life insurance need. Enter your own figures in the BoringToolsKit term life insurance calculator.
- The needs-based method totals income replacement, debts, and goals, minus existing assets. (Source: NAIC)
- Term life is far cheaper per dollar of coverage than whole life for a fixed term. (Source: NAIC)
- Ladder policies of different terms can match needs that shrink over time. (Source: BoringToolsKit calculation methodology)
How this calculator works
Formula
Coverage need = income x years to cover + debts + college costs - existing assets.
Worked example
$80,000 income for 10 years, $300,000 of debts, $100,000 for college, minus $50,000 of assets: a $1,150,000 need.
Assumptions to verify
- Needs-based method, not a multiple of income.
- Existing liquid assets offset the need; retirement accounts are often excluded.
Frequently asked questions
How much term life do I need?
A common floor is 10x income, but the needs-based total including debts, college, and assets is more accurate.
What term length should I choose?
Match the years your dependents rely on your income, often until children finish school.
Cite this tool
BoringToolsKit. “Term Life Insurance Calculator.” boringtoolskit.com/term-life-insurance-calculator/. Free to reference in articles, syllabi, and answer posts with a link.
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Worked example: where $753,000 comes from
Take a household earning 60,000 a year with 12 years until the youngest child finishes school, 18,000 of remaining debt, 40,000 of expected college cost, and 25,000 in liquid assets. The formula runs in a fixed order: multiply first, then add, then subtract.
Step 1: 60,000 x 12 = 720,000, the income-replacement term. Step 2: 720,000 + 18,000 = 738,000. Step 3: 738,000 + 40,000 = 778,000. Step 4: 778,000 - 25,000 = 753,000. The page prints $753,000.
As shares of that total, income replacement is 720,000 / 753,000 = 95.6 percent, debts and college together add 7.7 percent, and assets subtract 3.3 percent. The levers differ in size: each extra year of coverage adds exactly 60,000, while each extra dollar of assets removes exactly one. Raising assets from 25,000 to 50,000 drops the result to 728,000.
Boundary cases: zero floors, negatives, and discounting
The guard rejects only two things: income below 0 and years at or below 0, which return the 'Check the inputs' block instead of a number. Everything else passes through. A typo that sets assets to -5,000 is not caught; it subtracts a negative, so 60,000 x 10 years with no debts, no college and assets -5,000 returns 600,000 + 5,000 = 605,000, overstating the need by 5,000.
The zero floor is applied last, so only the display is floored. With income 50,000, years 5, debts 10,000, college 0 and assets 400,000, the raw value is 250,000 + 10,000 - 400,000 = -140,000; the clamp shows $0 while the summary line still prints the inputs that produced the negative.
The figure is also undiscounted: 12 years of 60,000 counts as 720,000 in today's dollars, but discounted at 4 percent the same stream is worth about 563,000, roughly 157,000 (22 percent) less. Decimals are not rounded away either: with debts, college and assets at 0 and years = 1, an income of 1,234.56 renders as $1,234.56.